0=6a^2+24a+18

Solution for 0=6a^2+24a+18 equation:

0=6a^2+24a+18

We move all terms to the left:

0-(6a^2+24a+18)=0

We add all the numbers together, and all the variables

-(6a^2+24a+18)=0

We get rid of parentheses

-6a^2-24a-18=0

a = -6; b = -24; c = -18;
Δ = b2-4ac
Δ = -242-4·(-6)·(-18)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*-6}=\frac{12}{-12}
=-1
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*-6}=\frac{36}{-12}
=-3
$